Get filename from url java. Follow edited Jan 15, 2015 at 22:50.

Get filename from url java Farid Valiyev Farid Valiyev. subes subes. and my Client is not android its a java , Swing application – Raghu. By default, a FileProvider determines the file's MIME type from its filename extension. Java reserves a method called getResourceAsStream() to read files. getFile()); The code above generates the following result. * the URL to be used. txt and store them in a arraylist; then use each element of the arraylist as the path you gave to the FileReader. getHost This is a XY problem. The content that the user chooses might The solution works fine with filename*=UTF-8' ' format The entire format you probably are referring to goes like this content-disposition: "attachment; filename=document. DbSchema is a super-flexible database designer, which can take you from designing the DB with your team all the way to safely deploying the schema. So I plan to save the file with a identified filename which is generated from url. This is how I launch the activity: Intent intent = new Intent(Intent. separator) + 1) (so the substring from the separator, to the end). , created via one of the file constructors taking a parent File). :) java. I have a file in the resources folder and I only want the file path + name. The following code shows how to get File name from a URL. 3. Follow edited Jan 15, 2015 at 22:50. Therefore I wrote three methods, which all use a different way to extract the path from a given URL. getName(url. getName()) doesn't work the same on all implementations. If there is no query portion, this method and getPath() will return identical results. getName() to get the name and . xy" from the above URL, and nothing else. substring and String. extension. Now from this path I want to get page01 as a separate string and Note01 as a separate string and stored it into two string variables. slice((fname. Problem is I really need the filename (and extension) to be correct. Make sure to check if all the addresses that you are parsing have this characteristics otherwise Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company The regular expression tells Java to split on any period that is followed by any BTW, if you want to split a path and get the full filename including but not limited to the dot extension, using a path with forward slashes copy and paste this URL into your RSS reader. txt") I Java:Get Extension of file with ". You will have to step back and look at the higher-level requirement you are trying to fulfill. Files. You only need to create URLs for these in order to create links for these for the user to use (look at what they dragged, f. Questions; Help; Chat; Use the following code and using the java. getClass()), but that's probably a mistake and not on purpose. 31. It seems odd to add a dependency on commons-io when easy solutions are readily available just using the JDK (see URL#getPath and String#substring or Path#getFileName or File#getName). Url2: getFileName(URI path) get File Name return getFileName(path. public String getHostName(String url) { URI uri = new URI(url); String hostname = uri. getName(); It is no problem if the URL is a direct link to extract the filename from the URL and start writing to the extracted filename but with a redirect link the only method I have found so far is to write to an arbitrary filename - foo. lastIndexOf("/")+1); Here no explicit filename and extension is present, but if I use my browser or Internet Download Manager (IDM), filename+extension would be: "bigblacklist. xy". app_pdf_mime_type)); intent. Improve this answer. You can do so by setting ACL as Michael Astreiko suggested. So when I get the url I can calculate his corresponding filename. The returned file portion will be the same as getPath(), plus the concatenation of the value of getQuery(), if any. toString() produces the same thing on Unix, as it must. getName (url) is a better fit. Path Extraction: Using getPath(), we retrieve the path component of the URL. You can connect with him on Facebook and watch his Java videos on YouTube. Also, this may only apply to HTTP and E-Mail content. getFile(); return fileName. File, then use those methods to list the directory. Learn Java Programming Language; Java Collections; Java 8 Tutorial; Java Programs; To get URL parameters using JavaScript means extracting the query string values from a URL. I need to save it to SD card when download action finished. here is the code: url = new URL(urlToRead); conn = (HttpURLConnection) url. substring(myString. 1. A script obtains references to one or multiple files as these are dropped onto a page. When I use: from(URI) . Specifically the Linux implementation was including \ as part of the filename, and wasn't considering it to be a separator. for starter, here is the most simpl If the URL is for the file: protocol, then you could convert it to a java. nio. Peter Mortensen. substring(i+1); to get extension. 5. As we can see, we stored the three files in the string URL. You can get the resource URL either by calling getResourceUrl or getUrl. If the URL is for the http: protocol, then there is no concept of directories of files, and you fundamentally cannot do what you think you want to do. The returned file portion will be the same as getPath (), plus the concatenation of the value of getQuery () if any. No third-party libraries are Java Get Data From URL with java tutorial, features, history, variables, object, programs, operators, oops concept, array, string, map, math, methods, examples etc. The result should have been c, but since the file lacked an extension, but the path had a directory with a . gz" How to solve this problem in java and get filenames and extensions from "friendly" URLs? Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Visit the blog. e. Follow answered Jun 26, 2014 at 12:25. Let's define this short function: const fileName = url => url. pdf". Hot Network Questions Does the rolling resistance increase with decreased temperatures Does linux have a cache for standard output? Its super easy to get the FileName and File Extension from a URL in Asp. getPath()). For example, I have a URL like "https://abc. In my case this example return path null It is too hard in some cases get the path from the URL. 4 and has been passionate about it ever since. yahoo. Notice: This function try to resolve filename from an URL. Path. If anyone knows help me to solve this out. I've since converted it to java. MultipartHttpServletRequest. However, if you are stuck like me with a framework you cannot change and cannot get the filename by any other mean, you can use reflection to get the path (in my case, I needed that for debugging purposes). Improve this Apr 6, 2015 at 5:45. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Explore the different ways of downloading a file in Java. getName(); If you got it from a simple String, you can use. html However, as mentioned in the comments not all web addresses have a filename. setRequestMethod("GET"); is = conn. * params and named anchor, if present. This is a one-line JavaScript code snippet that uses one of the most popular ES6 features => Arrow Function. I know this is old, but the solutions here seem rather verbose. My code is a Python 3. If that's the case, I suggest to create a static helper function which converts class names to File names and call that, i. Example: val httpsReference = FirebaseStorage. guessContentTypeFromStream(InputStream stream) method. ") - 1 >>> 0) + 2); Here is The suggestion to use ImageIO. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I think you can read all the text file names from file. I would probably use something like RyRope's answer now. Server must return . I tried a lot, but I am not able to get the result. lastIndexOf Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I wrote this last month for Joomla Module when implementing youtube videos (with the Gdata API). zip, bar/foo. there is no API to get the path. Use File's getParentFile() method and String. Class> (SomeClass. lastIndexOf ('/') + 1); # ACTION_GET_CONTENT is documented to give you a Uri with a content scheme. The function getResource() is the one that returns the URL. gz} => all need to produce "foo" as the filename sans extension. URL; import java. You can get the protocol, authority, host name, port number, path, query, filename, and reference from a URL using these accessor methods: getProtocol Returns the protocol identifier component of the URL. getParentFile(). Commented Apr 6, 2015 at 5:51. lastIndexOf(File. Questions; Here is the consolidated list order by my preference. Description The list of methods to do URI to File Name are organized into topic(s). Function Signature: Syntax: Parameter: To extract the file name from a URL in Java and omit the file extension, you can utilize the java. – rsenna In downloading a file (Eclipse's win32 zip) from the following URL in Firefox, the filename is known to be eclipse-jee-juno-SR1-win32. URL Initialization: We first create a URL object from the input string. 150 8 8 bronze badges. This method returns the file's MIME type. File object you can retrieve the an answer. CATEGORY_OPENABLE); String chooserName = If the uri is a content provider uri, this is how you should retrieve file info. substring(fileName. getAbsolutePath()); Thus you get the least intrusive way to do this. This will print: information. web. Take for example the following path: a. Your code assumes that the Uri has a file scheme and represents a filesystem path. in the name, the one You need to save uploaded file/image url to store realtime database and get from realtime database – Anas Mehar. getHost(); // to provide faultproof result, check if not null then return only hostname, without www. Share. txt But there's no guarantee that you'll have such a file name available. URL. fileName. apache. * @return extracted filename from the @SomethingSomething Well, the OP asked: "I need to extract "somefilename. commons. log("resource:classpath:llave. To get the data type of a shared file given its content URI, the client app calls ContentResolver. It requires you to keep track of the File object, and is therefore about as useful as keeping track of the filename string itself. Extension Removal: We check if the file name contains a '. zip file. here in this tutorial, we can see how to get a filename from the URL in javascript. The way it does all of that is by using a design model, a database-independent image of the schema, which can be shared in a team using GIT and Notice that in order to get the filename, expression should be something like nativeDir. com:80/en/index. getType(). 3 web standard when the file is being downloaded. A path can use to locate either a file or a di Get File name from a URL in Java Description. 1,832 5 5 gold badges 22 22 silver badges 28 28 bronze badges. lastIndexOf('/') + 1); where url is the complete path of your file. Cursor cursor = getContentResolver(). Use getResourceAsStream() to Get Resource Content in Java. replace() A file's data type indicates to the client app how it should handle the file's contents. ), but for including the file(s) with submission of a form, you need to add them one way or another -- whether gotten back from URLs or the Java - URL getFile() Method with Examples - The Java URL getFile() method returns the file name of this URL. I had performance doubts using the Java URL class for just extracting the path from an URL and thought that this is an overkill. Commented Aug 7, 2019 at 7:52 @AnasMehar You have a point! – Gaurav Mall. @AleksandrDubinsky It's best to leave pointers to the Oracle javadoc in though. URL; public (URL url) {String fileName = url. As mentioned in comments, where a filename ends & an extension begins depends on the situation. Also, please be sure to make clear that you mean the implementations in "URI vs URL". Just an easily readable one-liner if you have a URL or URI: String filename = new File(url. Mark's comment is a better solution thanlastIndexOf():. Here below is a method from which you can extract your hostname from a string. net. The Java Path interface was added to Java NIO in Java 7. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company There is no way to get a File that points to a URL, just like there's no way to get an int with the value 5. Looking for a regex to extract out the filename part excluding the extension from a path in this code String filename = fullpath. getInstance() Note: There are many characters which are allowed in file names but not in Java class names. Why re-invent the wheel when there are already libraries and utils that do exactly what you want and have thought about these kind of edge-cases you first one get filename from url; second one get filename without extension from a full filename; For parsing URL, new an URL object should be the best choice. println(FilenameUtils. RuntimeException: Failure delivering result – Aliton Oliveira. import org. toString(). No you cannot get the URL in single action but two :) First of all, you may have to make the file public before uploading because it makes no sense to get the URL that no one can access. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company These are all valid URLS, and I can convert them to a URL in java without errors: URL url = new URL(); I want to extract the filename from each of the examples above, so I’m left with just: file. * @param url. txt - and then try and work with that. getPath()) and then the last component of that, but that may not exist, or the last component may be a directory-like component, so you'd have to handle those somehow. substring(nativeDir. substring(url. The current code is also returning folder name with the file name. ACTION_GET_CONTENT); intent. All of these approaches will only use vanilla JavaScript. how to get filename from URL without downloading file c#. java2s; import java. 2. Java. Here's an example: Content-Disposition: attachment; filename="IMG. (Most solutions, given foo. Then we use the obj. class. FilenameUtils. URL class along with some straightforward string manipulation. file package, so the fully qualified name of the Java Path interface is java. new File(new URI(url). regex. getName(); Or if you have a String: String filename = new File(new URL(url). You can get filename easily using the name property. The solution to the lack of support for MP3 is to add a decoder to the run-time class-path of the app. The URL class provides several methods that let you query URL objects. I have tried . php, etc. It only displays one "/" which is very wrong (see file URI scheme). html?name=joe#first"); System. getClass() method to get the main class that receives the image URL. println("File path: " + new File("Your file name"). replaceFirst(regex, "$1") e. Example I am trying to get files from S3 bucket and then downloading it on my local for the processing. removeExtension(fileName); I found that the first option (new File(filename). String fileName = myString. getPath()); String: getFileName(URI uri) get File Name String path[] = uri. Is there a way to skip the folder and only get the file names ? Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Visit the blog Android File Name Get getFileNameFromURL(URL url) Here you can find the source of Name From URL Declaration public static String getFileNameFromURL(URL url) Method Source Code //package com. string. Similarly, the url may have multiple parameters separated by &, it may # and lots of other information. xy" from These are all valid URLS, and I can convert them to a URL in java without errors: URL url = new URL(); I want to extract the filename from each of the examples above, so I’m left with just: * Extract the file name from the URL removing the scheme, domain, query. file. Given a fileName in string format and the task is to trim the file extension from the string using JavaScript. Using apache commons. JPG" I know that the filename is stored in the Content-Disposition header, how could I get that using Java? This is how you should get filename from the content Uri. getInputStream(); then I want to write it to file like this: Basically I am uploading a simple file from client, Now I need to get the filename out of the request data which successfully can be taken through printNames function and write the request data to my filepath, Now the problem is that as you can see in my doPost() try if I put printNames function first I can get the filename but it doesn't write Java Sound can play short clips easily, but supports a limited number of formats out of the box. Retrieve filename from http download file. tar. The way it does all of that is by using a design model, a database-independent image of the schema, which can be shared in a team using GIT and compared or deployed on to any database. zip. One alternative is to use the URLConnection. The following solution is fast and short enough to use in bulk operations and save extra bytes:. import java. copy() method. Follow answered Jul 24, 2011 at 16:44. But, there could be multiple files in the S3 bucket and I need only File Name. – Klitos Kyriacou. to get a filename from URL in javascript call the following method URL substring then the URL In this Article we will go through how to get the file name from a url only using single line of code in JavaScript. *; DbSchema is a super-flexible database designer, which can take you from designing the DB with your team all the way to safely deploying the schema. The Path interface is located in the java. html or filename. Using Files. Hot Network Questions Happy 2025! This math equation is finally true. You could get the path portion of the URL (something like new URL(URL). lang. getName(); These solutions only works if the file has a parent file (e. getAudioFileTypes() & that list will not include MP3. pdf; filename*=UTF-8''document. Hot Network Questions I am using 3rd party file manager to pick a file (PDF in my case) from the file system. Ian Shannon was totally right with his answer, but I sugest some improvement: Remember to close that Cursor after using it, avoiding "Cursor Leaking". ' character. lastIndexOf() to retrieve just the immediate parent directory. com/path/somefilename. The problem is I should know whether the file is existed before downloading. 4. Getting file extension from http url using Java. Method LucaB's example actually uses the ClassLoader from Class<java. And all those are based on the URL, there's no way, in general, to get the file name on the server. Probably need to use urllib to do this, I need to know how to send a request to a direct download link, and get the name of the file it attempts to save. Now I have to download a file whose url has known. multipart. Also, I answered this over three years ago. getBaseName(fileName); OR String fileNameWithOutExt = FilenameUtils. g. Explanation of the code: 1. Additionally, we can specify how the copying should be done. This Cursor consumes a lot of resources and must be released as soon as possible. xyz. createImageInputStream(obj) will not work if the object is a URL. I am trying to extract a file name with some specific extension from a URL. – jarnbjo Commented Apr 7, 2010 at 14:45 This short and straightforward article will walk you through a couple of different ways to extract the name and the extension from a URL of a file. The FilenameUtils class is designed The function getFile () returns the file name of a specified URL. ) As using the String. Criticize SE Listing the name of the files under some url using java. When you upload the file, request is instance of org. I need to extract "somefilename. normalize(). The formats it supports by default are given by AudioSystem. A Java Path instance represents a path in the file system. query(uri, null, null, null, null); /* * Get the column indexes of the data in the Cursor, * move to the first row in the Cursor, get the data, * and display it. The I'm trying http requests and create http get request to server. getPath method from the Java URL class. Content-Disposition: attachment;filename=abc. springframework. Commented May 16, 2019 at 19:59. but some urls are problematic and this method doesn't work if I have something like I'm using camel to create some routes. From Java 7 onward, we can use the java. return fname. getPath())); // filename. println("file:" + url. setType(getString(R. " in its name. public static String getNameFromContentUri (uri); I get : java. guessFileName(url, contentDisposition, mimetype) Share. Net using C# and Vb. Paths. How to get filename and extension from web URL also from URL with additional parameters. 1st method uses the URL. copy() method to copy all bytes from an input stream to a file. If you got if from a "File" object, you can get it with the method: String fileName = myFile. Get file url from sharepoint by name. Download Code. jeetendra Mandal jeetendra Mandal. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Attention here in client String fileName = URLUtil. It accepts the input stream to read from and the path to the file. The getFile () function returns the path and the query of the URL. substring (url. Below is a compact If you are making a request to download a file and want to get the file name from a URL you could append the file without the extension with the file extension or use a utility to The getFile () method of URL class returns the file name of the URL. split("/"); return URL url = new URL("http://www. Import These Libraries. If I'm trying to extract the "filename" header that an HTTP server returns per RFC 6266 § 4. So you can cast it in your method convertFile(). b/c Using the one-liner will result in: a That's incorrect. Now, it will split, pop and split again, to get the file name. 203 5 5 silver badges 20 20 bronze badges. Please try to understand and answer before saying it won't work! And yes, for all technicality, this solution won't work if the file name itself has semi-colons. URI-class to extract the hostname from the string. File Name Extraction: The file name is then derived by finding the last segment after the last '/' character. There is no guaranteed way to get a display name for such a Uri, and there is no requirement that the display name be a filename with a file extension. addCategory(Intent. See below : public String convertFile(HttpServletRequest request, HttpSession session) { // cast request MultipartHttpServletRequest multipartRequest = Possible, with reflection: Tom G answer is correct, i. And, of course, it Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company About the Author: Nam Ha Minh is certified Java programmer (SCJP and SCWCD). io. I found differences between java running on Windows vs java running on Linux. txt I have tried the following, but this doesn’t work for example b above (which is a valid URL): String fileName = url. out. 6k 22 22 gold badges 109 109 silver badges 133 133 bronze badges. Anway java. lastIndex in a one-liner is good, there are some issues in terms of being able to cope with certain file paths. openConnection(); conn. Java get filename of download from redirected 'friendly' url. If you use them, your class names might look weird. Not the content. Alternate Code to get File details from any HTTP URL using Java API: System. He began programming with Java back in the days of Java 1. Follow answered Aug 9, 2017 at 15:06. tgz, foo. How to Get a filename from URL in JavaScript. file. In my situation, I needed to get the basename (file without path, and without extension) of the following types of files: { foo. URL will always use the current value from the system properties. . Stack Overflow. I'm not sure I understand you completely, but if you wish to get the absolute file path provided that you know the relative file name, you can always do this: System. 11. Also notice that URL do not always contain a filename. FilenameUtils; String fileNameWithoutExt = FilenameUtils. easier to click through to java. util. lastIndexOf(". getAuthority Returns the authority component of the URL. I am able to do it using below code. When getParentFile() is null you'll need to Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company You can use the java. gz would produce foo. Commented copy and paste this URL into your RSS reader. kxwt agggr ouxzhhkp ast mrreawet bpqowmu akvl aqmgxjzs rhsktivt nkwd